0=2y^2-90

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Solution for 0=2y^2-90 equation:



0=2y^2-90
We move all terms to the left:
0-(2y^2-90)=0
We add all the numbers together, and all the variables
-(2y^2-90)=0
We get rid of parentheses
-2y^2+90=0
a = -2; b = 0; c = +90;
Δ = b2-4ac
Δ = 02-4·(-2)·90
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*-2}=\frac{0-12\sqrt{5}}{-4} =-\frac{12\sqrt{5}}{-4} =-\frac{3\sqrt{5}}{-1} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*-2}=\frac{0+12\sqrt{5}}{-4} =\frac{12\sqrt{5}}{-4} =\frac{3\sqrt{5}}{-1} $

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